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A 62.0 kg person in

a rollercoaster moves 29.2 m/s
at the bottom of a curved track
of radius 33.7 m. What is the normal
force acting on the person?
(Unit = N)

1 Answer

1 vote

m=62kg

v=29.2m/s

r=33.7

FN=mv²/r+ mg

=62*29.2²/33.7 + 62*9.81

= 2176.88N

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