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Which of the following lines are perpendicular to 3x-y=10?

1.y-2= 1/3 (3x+36)
2.y=3x+5
3.x + 3y=27
4. y=-1/3x+17

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Answer:

Number 3 and 4

Explanation:

We know a line is perpendicular to another line if their slopes are the opposite reciprocals of each other

From the equation of 3x-y=10, we write this in slope-intercept form as

y=3x-10

Therefore, the slope of this line is 3

The opposite reciprocal of 3 is -1/3

Looking at the answer choices, 3 and 4 have slopes of -1/3

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