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A parabola with its vertex at (2,5) and its axis of symmetry parallel to the y-axis passes through point (22,365). Write an equation
of the parabola. Then find the value of y when x = 12.
An equation is
Elio Mendoza
When x = 12, y =

1 Answer

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A parabola with its vertex at (2, 5) and its axis of symmetry parallel to the y-axis can be represented by the equation:

y = a(x - 2)^2 + 5

where a is a coefficient that determines the shape and direction of the parabola.

We can find the value of a by substituting the coordinates of the given point (22, 365) into the equation:

365 = a(22 - 2)^2 + 5

Then, we can solve for a by rearranging the terms and solving for a:

360 = a(20^2)
a = 360 / (20^2)
a = 0.225

Now that we have found the value of a, we can substitute it back into the equation to get the final equation of the parabola:

y = 0.225(x - 2)^2 + 5

To find the value of y when x = 12, we can substitute 12 for x in the equation:

y = 0.225(12 - 2)^2 + 5
y = 0.225(10^2) + 5
y = 2.25 + 5
y = 7.25

Therefore, the value of y when x = 12 is 7.25.
User Noki
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