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39 votes
Devide (a2+ 7a+ 12)÷ (a+3)​

User Abdul Yasin
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1 Answer

15 votes
15 votes

Answer:

(a - 3) • (a - 4)

Explanation:

The first term is, a2 its coefficient is 1 .

The middle term is, -7a its coefficient is -7 .

The last term, "the constant", is +12

Multiply the coefficient of the first term by the constant 1 • 12 = 12

Find two factors of 12 whose sum equals the coefficient of the middle term, which is -7 .

-12 + -1 = -13

-6 + -2 = -8

-4 + -3 = -7 That's it

Rewrite the polynomial splitting the middle term using the two factors, -4 and -3

a2 - 4a - 3a - 12

Add up the first 2 terms, pulling out like factors :

a • (a-4)

Add up the last 2 terms, pulling out common factors :

3 • (a-4)

Add up the four terms

(a-3) • (a-4)

Really hope this helps :)

User Ubermensch
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