Answer:
// Solve equation [1] for variable x
[1] x = -2y + 5
// Plug this in for variable x in equation [2]
[2] 3•(-2y+5) + 5y = 14 [2] - y = -1
// Solve equation [2] for variable y
[2] y = 1
// Now we know this:
x = -2y+5 y = 1
// Use the y value to resolve x
x = -2(1) +5 = 3
Workaround:
{x,y} = {3,1}