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researchers have collected data on the hours of studying in a week and the exam grade of a student. you are given the data below (10 points). hint: this questions is similar to q1 in hw7. hours of studying exam grade 1 55 3 75 4 80 3 85 6 99

User Underlines
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The t-test value for the given collected data of hours of studying and exam grade is equal to 10.45.

As given in the question,

n = 5

Mean of the data ( time ) μ₁ = ( 1+ 3 + 4 + 3+ 6)/ 5

= 3.4

Mean of the exam grade μ₂ = ( 55 + 75 + 80 + 85 + 99) / 5

= 78.8

Standard deviation of time σ₁ = 1.82

Standard deviation of exam grade σ₂ = 16.04

Standard error of time = σ₁/√n

= 1.82 / √5

=0.81

Standard error of time =σ₂/√n

= 16.04/ √5

=7.17

Difference in mean of time and exam grade = 78.8 - 3.4

= 75.4

Standard error of difference 'S.E'= √ (0.81)² + (7.17)²

= 7.215

t - test for the given data

= | μ₁ - μ₂| / S.E.

= | 3.4 - 78.8| / 7.215

= 75.4 / 7.215

= 10.45

P value and statistical significance:

Two-tailed P value is smaller than 0.0001

Therefore, the t-test value for the given collected data is equal to 10.45.

The above question is incomplete , the complete question is:

Researchers have collected data on the hours of studying in a week and the exam grade of a student. you are given the data below (10 points). hint: this questions is similar to q1 in hw7.

hours of studying exam grade

1 55

3 75

4 80

3 85

6 99

Calculate the t -test and interpret the data?

User Pvg
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