111k views
4 votes
In a race, Jason's position was −11 1/5 feet relative to the leader after 1 3/4 minutes. On average, how much did Jason's position relative to the leader change per minute?

Enter your answer as a mixed number, in simplified form, in the box.

[ ] ft

User Cyberixae
by
4.4k points

1 Answer

4 votes

Answer:

the change in Jason's position relative to the leader per minute is [-] ft/minute.

Explanation:

First, we need to convert 1 3/4 minutes to fractional minutes. We can do this by expressing 1 3/4 as 7/4 minutes.

Next, we need to find the change in Jason's position relative to the leader in fractional minutes. We can do this by dividing Jason's position relative to the leader by the time in fractional minutes: -11 1/5 feet / (7/4 minutes) = -33/5 feet / (7/4 minutes).

Finally, we need to convert this result to feet per minute. We can do this by multiplying the numerator by the reciprocal of the denominator: -33/5 feet / (7/4 minutes) = -(33/5 feet) * (4/7 minutes/feet) = -24/7 feet/minute.

The change in Jason's position relative to the leader per minute is -24/7 feet/minute. The negative sign indicates that Jason's position relative to the leader decreased over time.

In simplified form, the change in Jason's position relative to the leader per minute is [-] ft/minute.

User Irmakoz
by
4.6k points