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Find the equation of a circle centered at (3, -3) and passing through P(3, 0).

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Answer:

(x - 3)² + (y + 3)² = 9

Explanation:

the equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k ) are the coordinates of the centre and r is the radius

the radius r is the distance from the centre to a point on the circle.

given (3, - 3 ) is the centre and (3, 0 ) is a point on the circle

since the x- coordinates of both points are 3 then r is the absolute value of the difference of the y- coordinates, that is

r = | - 3 - 0 | = | - 3 | = 3

then equation of circle is

(x - 3)² + (y - (- 3) )² = 3² , that is

(x - 3)² + (y + 3)² = 9

User Amna Ali
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