Question

A 2200 kg auto moving at 12.0 m/s runs into a 3800 kg truck that is moving in the opposite direction at 5.00 m/s. The collision is perfectly inelastic. What is the change in internal kinetic energy after the collision? Include the appropriate units.

Answer 1

Answer: We have vf = 7.57 m/s, which is the speed of the car (and the truck) after the collision.

Step-by-step explanation:

p (auto) = 2200 kg * 12 m/s = 26,400 kg m/s p (truck) = 3800 kg * 5 m/s = 19,000 kg m/s After the collision, we have p = (2200+3800)*vf = 26400+19000 p = 6000*vf = 45,640 Therefore, we have vf = 7.57 m/s, which is the speed of the car (and the truck) after the collision.