Question

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Answer 1

`0.5√(16a^2)=-2a \quad \text{if}\;\;a < 0`

`-5√(y^2)=-5y \quad \text{if}\;\;y > 0`

`3√(c^2)=3c \quad \text{if}\;\;c \geq 0`

`-√(9y^2)=3y \quad \text{if}\;\;y < 0`

Explanation:

`0.5√(16a^2)\;\; \text{if}\;\;a < 0`

`\implies 0.5√(16)√(a^2)`

`\implies 0.5\cdot 4√(a^2)`

`\implies 2√(a^2)`

`\implies 2 \cdot -a`

`\implies -2a`

`-5√(y^2)\;\; \text{if}\;\;y > 0`

`\implies -5y`

`3√(c^2)\;\; \text{if}\;\;c \geq 0`

`\implies 3c`

`-√(9y^2)\;\; \text{if}\;\;y < 0`

`\implies -√(9)√(y^2)`

`\implies -3√(y^2)`

`\implies -3 \cdot -y`

`\implies 3y`