To find the distance from point P to point F, we can use the Law of Sines on triangle PYF. The Law of Sines states that for any triangle with side lengths a, b, and c and opposite angles A, B, and C, the following holds:
a/sin(A) = b/sin(B) = c/sin(C)
In this case, we can let a = PF, b = PY, and c = YF. We also know that A = 30° and C = 60°. We can solve for PF by substituting these values into the equation and solving for a:
PF/sin(30°) = PY/sin(60°)
PF = PY * sin(30°) / sin(60°)
To find PY, we can use the fact that the measure of the angle from you to your friend standing on the shore is 30°. This means that triangle PYF is a 30-60-90 triangle, which means that the ratio of the side lengths is 1:√3:2. Since PY is the shorter leg of the triangle, it must be half the length of the hypotenuse, or YF. This means that PY = YF / 2. Substituting this into the equation above, we get:
PF = (YF/2) * sin(30°) / sin(60°)
PF = YF / 2
Since YF = 12 feet, this means that PF = 6 feet.
To find the distance between you and the shore line, you can use the Pythagorean Theorem on triangle PYF. The Pythagorean Theorem states that in any right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides. In this case, the hypotenuse is YF, and the other two sides are PY and PF. We can set up the equation as follows:
YF^2 = PY^2 + PF^2
12^2 = PY^2 + 6^2
144 = PY^2 + 36
108 = PY^2
PY = sqrt(108)
PY = 6*sqrt(3)
Therefore, the distance between you and the shore line is 6*sqrt(3) feet.
In order to prove that the two triangles are congruent, we would need additional information about the side lengths and angles of triangle PYF. Congruent triangles have the same side lengths and the same angles, so we would need to know that all of the sides and angles of triangle PYF are the same as the corresponding sides and angles of another triangle. Without this information, we cannot prove that the two triangles are congruent