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What is the equation of the line that passes through the point(-6,-7) and has a slope of 1/3

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Answer:

The equation of the line that passes through the point (-6, -7) and has a slope of 1/3 is:

x - 3y + 15 = 0

Explanation:

The equation of a line in slope-intercept form is given by y = mx + b, where m is the slope of the line and b is the y-intercept (the point at which the line crosses the y-axis).

To find the equation of the line that passes through the point (-6, -7) and has a slope of 1/3, we can use the point-slope form of a line:

y - y1 = m(x - x1)

Where (x1, y1) is a point on the line and m is the slope of the line.

Plugging in the given values, we have:

y - (-7) = (1/3)(x - (-6))

Which simplifies to:

y + 7 = (1/3)x + 2

Multiplying both sides by 3, we have:

3y + 21 = x + 6

Subtracting 21 and 6 from both sides, we have:

3y - x - 15 = 0

Therefore, the equation of the line that passes through the point (-6, -7) and has a slope of 1/3 is:

x - 3y + 15 = 0

User Kuba Holuj
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