Answer:
0.67 moles of NH3 are required to react with 32.2 grams of O2.
Step-by-step explanation:
To find the number of moles of NH3 required to react with 32.2 grams of O2, you will need to balance the chemical equation for the reaction and use the balanced equation to determine the mole ratio between the reactants.
The balanced equation for the reaction of NH3 with O2 is:
2 NH3 + 3 O2 -> 2 N2 + 6 H2O
From this equation, we can see that for every 2 moles of NH3 that react, 3 moles of O2 are also consumed. Therefore, the mole ratio between NH3 and O2 is 2:3.
Since we are given the mass of O2 in grams and we want to find the number of moles of NH3, we can use the molar mass of O2 to convert the mass to moles. The molar mass of O2 is 32.0 g/mol. Therefore, 32.2 grams of O2 is equivalent to 32.2 / 32.0 = 1.00625 moles of O2.
To find the number of moles of NH3 required, we can use the mole ratio to convert from moles of O2 to moles of NH3. Since the ratio is 2:3, we can multiply the number of moles of O2 by (2/3) to find the number of moles of NH3:
1.00625 moles O2 * (2 moles NH3 / 3 moles O2) = 0.67 moles NH3
This means that 0.67 moles of NH3 are required to react with 32.2 grams of O2.