Answer:
Step-by-step explanation: h(t)=-16t2+85
Let h(t)=0 to find when the object will hit the ground
0=-16t2+85
Solve for t=?
We need to get t term on its own
Take 85 from both sides
0-85=-16t2+85-85
-85=-16t2
To get t term on its own
Divide both sides by -16
-85/-16=-16t2/-16
5.3=t2
We have to solve for t squared that means we must take the square root of both sides
the square root of 5.3=gives + or - 2.3 seconds we can't have negative time so discard -2.3 seconds