Question

A cannonball is shot (from ground level) with an initial horizontal velocity of 20 m/s and an initial vertical velocity of 30 m/s. What's the maximum height reached by the cannonball

Answer 1

maximum height = 46m

Step-by-step explanation:

Vx = 20m/s

Vy = 30 m/s

gravity = 9.8 m/s/s

final velocity = initial velocity - gravity • time

0 = 30m/s - 9.8m/s/s • time

subtract 30m/s from both sides

-30m/s = - 9.8m/s/s • time

divide both sides by -9.8m/s/s

3.06 s = time

height = initial velocity • time - 1/2 • gravity • time^2

height = 30m/s • 3.06s - 1/2 • 9.8m/s/s • 3.06s ^2

height = 46m

the maximum height is equal to 46m