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Help me thank u ……..

Help me thank u ……..-example-1
User TheZuck
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2 Answers

2 votes

Answer: y=5/3 x-2

Explanation:

y=mx+b

(3,3) (0,-2)


\displaystyle\\\boxed{(x-x_1)/(x_2-x_1)=(y-y_1)/(y_2-y_1) }

x₁=3 x₂=0 y₁=3 y₂=-2


\displaystyle\\(x-3)/(0-3) =(y-3)/(-2-3) \\\\(x-3)/(-3) =(y-3)/(-5) \\

Multiply both parts of the equation by -5:


\displaystyle\\(5)/(3)(x-3)=y-3 \\\\\ (5)/(3) x-5=y-3\\\\ (5)/(3) x-5+3=y-3+3\\\\\ (5)/(3) x-2=y\\\\Thus,\ y=(5)/(3)x-2\\

User Frankster
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4.6k points
5 votes

Answer:

y = 5/3 x - 2

Explanation:

y = mx + b

The m stands for the slope (steepness of the line)

The y stands for the y intercept.

The y intercept is where on the y axis does the line cross? It crosses at (0,-2) so we say that it crosses at -2.

Slope. Start at the bottom point, from that point go vertically up 5 spaces and then go 3 spaces horizontally right. slope 5/3

User EeKay
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5.9k points