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What is the equation in standard form of the line that passes through the point (6,-1) and is parallel to the line represented by.

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Answer:

Explanation:

y = mx + b

In this equation, m is the slope of the line and b is the y-intercept (the point at which the line crosses the y-axis).

To find the equation of a line that passes through a given point (x1, y1) and is parallel to another line with slope m, you can use the point-slope formula:

y - y1 = m(x - x1)

In this case, the line passes through the point (6, -1) and is parallel to the line represented by y = mx + b. Substituting these values into the point-slope formula, we get:

y - (-1) = m(x - 6)

This is the equation of the line in point-slope form. To put the equation in standard form, we can rearrange the terms to get:

y = mx - 6m + 1

This is the equation of the line in standard form.

I hope this helps! Let me know if you have any further questions.

User Sander Mertens
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