Question

What volume (in liters, at 253 K and 6.54 atm) of chlorine gas is required to react with 7.89 g of P? 2P(s) + 5Cl2(g) → 5PCl5(s)

Answer 1

7.89 grams of phosphorus reacts with 45.15 grams of chlorine

Step-by-step explanation:

For reacting with 2 mole of P react with 5 mole of Cl2 gas

Molecular weight of phosphorus = 30.97

Molecular weight of 2 mole of phosphorus = 2 * 30.97 = 61.94 grams

Molecular weight of Chlorine molecule = 70.9 grams

Weight of 5 moles of Chlorine molecule = 5 * 70.9 grams = 354.5 grams

61.94 grams of phosphorus reacts with 354.5 grams of chlorine

7.89 grams of phosphorus reacts with 354.5/61.94 * 7.89 grams of chlorine

7.89 grams of phosphorus reacts with 45.15 grams of chlorine