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If 4.644.64 mol of NO2NO2 occupy 25.925.9 L, how many liters will 2.732.73 mol of NO2NO2 occupy at the same temperature and pressure

User Univerio
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1 Answer

29 votes
29 votes

Answer:

I will assume that the moles are all mistyped and will change them to:

4.64, 25.9, and 2.73.

15.2 liters

Step-by-step explanation:

Both situations can be described using the ideal gas law:

PV=nRT,

where P, V, and T are the pressure, volume, and temperature (in degrees K). n is the number of moles. R is the gas constant.

First NO2 : P1(25.9L) = (4.64moles)RT

Second NO2: P2V2 = (2.73moles)RT2

Divide one equation by the other:

(P1(25.9L) = (4.64)RT1)

P2V2 = (2.73)RT2

The temperatures, pressures, and gas constants are unchanged, so we can cancel those to obtain:

(25.9L)/V2 = (4.64/2.73)

V2 = (25.9L)(2.73/4.64)

V2 = 15.2 Liters

User David Vezzani
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