216k views
1 vote
If m∠BOC = (3x + 1)° and m∠COD = (11x − 3)°, what is m∠COD?

13°
40°
69°
140°

If m∠BOC = (3x + 1)° and m∠COD = (11x − 3)°, what is m∠COD? 13° 40° 69° 140°-example-1

2 Answers

4 votes

Answer: d 140

Step-by-step explanation: I just took the test

User LWZ
by
5.1k points
4 votes

Answer:

D) 140°

Explanation:

Angles BOC and COD form a linear pair.

Therefore, the sum of the two angles is 180°.

⇒ m∠BOC + m∠COD = 180°

⇒ (3x + 1)° + (11x - 3)° = 180°

⇒ 3x + 1 + 11x - 3 = 180

⇒ 3x + 11x + 1 - 3 = 180

⇒ 14x - 2 = 180

⇒ 14x - 2 + 2 = 180 + 2

⇒ 14x = 182

⇒ 14x ÷ 14 = 182÷ 14

⇒ x = 13

To find the measure of angle COD, substitute the found value of x into the expression for m∠COD:

⇒ m∠COD = (11x - 3)°

⇒ m∠COD = (11 · 13 - 3)°

⇒ m∠COD = (143 - 3)°

⇒ m∠COD = 140°

User Mropa
by
5.5k points