Question

(5y+3)^2 -20=(5y-3)^2 LHS =RHS show that !!?​

Answer 1

It's not true = as you can see, the value of y is not the same, so the whole thing is false.

Explanation:

First, Solve for y:

(5 y + 3)^2 - 20 = 0

Add 20 to both sides:

(5 y + 3)^2 = 20

Take the square root of both sides:

5 y + 3 = 2 sqrt(5) or 5 y + 3 = -2 sqrt(5)

Subtract 3 from both sides:

5 y = 2 sqrt(5) - 3 or 5 y + 3 = -2 sqrt(5)

Divide both sides by 5:

y = 2/sqrt(5) - 3/5 or 5 y + 3 = -2 sqrt(5)

Subtract 3 from both sides:

y = 2/sqrt(5) - 3/5 or 5 y = -3 - 2 sqrt(5)

Divide both sides by 5:

Answer: y = 2/sqrt(5) - 3/5 or y = -3/5 - 2/sqrt(5)

___________________________

Solve for y:

(5 y - 3)^2 = 0

Take the square root of both sides:

5 y - 3 = 0

Add 3 to both sides:

5 y = 3

Divide both sides by 5:

Answer: y = 3/5