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Solve the problem.

Two cars leave a city and head in the same direction. After 5 hours, the faster car is 40 miles ahead
of the slower car. The slower car has traveled 275 miles. Find the speeds of the two cars.
(A) 55 mph and 63 mph
B) 80 mph and 88 mph
C 57 mph and 65 mph
D) 47 mph and 55 mph

User Aykut
by
5.5k points

1 Answer

7 votes

Answer:

A

Explanation:

Let x = speed of the faster car, y = speed of the slower car

after t = 5 hours, distance of slower car = 275 = 5 * y, so y = 275/5 = 55 mph

distance of faster car = 275 + 40 = 315 miles

then x = 315/5 = 63 mph

Answer: A

User Catalina Chircu
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5.2k points