Question

F(x) = 8 sin [2(x+3)] +9?

Answer 1

Explanation:

f(x) = 8 sin [2(x+3)] + 9

x = 8 sin [2(y+3)] + 9

isolate y
`(f^(-1)(x))`:

x/8 - 9 = sin[2(y+3)]

`sin^(-1)((x)/(8) - 9) = 2(y+3)`

= 2y + 6

`sin^(-1)((x)/(8) - 9) = 2y + 6\\sin^(-1)((x)/(8) - 9) - 6 = 2y\\(sin^(-1)((x)/(8) - 9) - 6)/(2) = y`