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64c³ +1 Factoring polynomials
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64c³ +1

Factoring polynomials

User David Bernard
by
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1 Answer

5 votes

Answer:

(4c + 1)(16c² - 4c + 1)

Explanation:

64c³ + 1 ← is a sum of cubes and factors in general as

a³ + b³ = (a + b)(a² - ab + b²)

64c³ + 1

= (4c)³ + 1³ [ with a = 4c and b = 1 ]

= (4c + 1)((4c)² - 4c(1) + 1²)

= (4c + 1)(16c² - 4c + 1)

User Fiorebat
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4.2k points
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