Answer: To calculate the horizontal distance of the bomber from the target when a bomb is released, we need to consider the constant velocity of the bomber and the time it takes for the bomb to fall from the height of the bomber to the ground.
We can use the following formula to calculate the horizontal distance traveled by an object moving at a constant velocity:
Distance = velocity * time
We can also use the formula for the distance traveled by an object falling under the influence of gravity:
Distance = initial velocity * time + (1/2) * acceleration * time^2
In this case, the initial velocity is 0, since the bomb is being released from rest at the height of the bomber. The acceleration due to gravity is 9.8 m/s^2.
To find the time it takes for the bomb to fall from the height of the bomber to the ground, we can set the distance traveled equal to the height of the bomber (100m) and solve for time:
100m = (1/2) * 9.8 m/s^2 * time^2
time = sqrt(100m / (1/2 * 9.8 m/s^2))
time = sqrt(20.4)
time = 4.47 seconds
Now that we have the time it takes for the bomb to fall, we can use the formula for the distance traveled at a constant velocity to find the horizontal distance of the bomber from the target when the bomb is released:
Distance = 50m/s * 4.47s
Distance = 223.5 meters
Therefore, the horizontal distance of the bomber from the target when the bomb is released is 223.5 meters.