Question

as part of a science experiment, Carson designs and creates a cushioned egg carrier. he puts an egg inside it and then drops it from a window to see whether his design can safely cushion the egg and keep it from breaking. the egg's height in feet x seconds after being dropped is given by 27 - 16x^2. after how many seconds will the egg hit the ground?

Answer 1

Answer: To find out how many seconds it will take for the egg to hit the ground, we need to find the value of x when the height of the egg is 0 feet. We can do this by setting the height of the egg equal to 0 in the equation 27 - 16x^2 and solving for x.

The equation for the height of the egg in feet x seconds after being dropped is given as:

27 - 16x^2 = 0

Subtracting 27 from both sides of the equation gives us:

-16x^2 = -27

Dividing both sides of the equation by -16 gives us:

x^2 = 27/16

Taking the square root of both sides of the equation gives us:

x = sqrt(27/16)

Plugging this value into the equation for the height of the egg gives us:

27 - 16(sqrt(27/16))^2 = 0

Simplifying this equation gives us:

27 - 16(27/16) = 0

Which simplifies to:

27 - 27 = 0

This equation is true, so the value of x that we found is a solution to the equation. This means that the egg will hit the ground after sqrt(27/16) seconds.

I hope this helps! Let me know if you have any other questions.