Question

Hydrazine (N₂H4), a rocket fuel, reacts with oxygen to form nitrogen gas and water vapor. The reaction is represented with the equation:

N₂H4(1) + O₂(g) → N₂(g) + 2H₂O(g)
How many grams of hydrazine are needed to produce 96.0g water?

Answer 1

Answer: To determine how many grams of hydrazine are needed to produce 96.0 grams of water, we can use the mole ratio between hydrazine and water in the chemical equation.

First, we need to convert the number of grams of water to moles. We can do this using the molar mass of water, which is 18.0 grams/mole:

96.0 g H2O / 18.0 g/mol = 5.33 moles H2O

Next, we can use the mole ratio between hydrazine and water in the chemical equation to determine the number of moles of hydrazine that would be needed to produce 5.33 moles of water:

1 mole N2H4 / 2 moles H2O = 0.5 mole N2H4

Finally, we can use the molar mass of hydrazine (32.0 grams/mole) to convert the number of moles of hydrazine to grams:

0.5 mole N2H4 * 32.0 g/mol = 16.0 grams N2H4

Therefore, 16.0 grams of hydrazine are needed to produce 96.0 grams of water.