Final answer:
There are 1.8066 x 10^24 bromide ions in 1.5 moles of MgBr2.
Step-by-step explanation:
To find the number of bromide ions in 1.5 moles of MgBr2, we need to consider the formula of MgBr2. In MgBr2, there are two bromide ions for every one Mg2+ ion. So, for each mole of MgBr2, there are two moles of bromide ions.
Therefore, in 1.5 moles of MgBr2, there would be 1.5 x 2 = 3 moles of bromide ions.
Since each mole contains 6.022 x 1023 particles, the number of bromide ions in 1.5 moles of MgBr2 would be 3 x 6.022 x 1023 = 1.8066 x 1024