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write an equation in standard form of the line that passes through the given point and has the given slope (-3,2) m=1

User Meziantou
by
8.5k points

2 Answers

2 votes

Answer:

Explanation:

The standard form of a line is Ax+By=C. To solve this problem, begin with the point-slope form
y-y_1=m(x-x_1). For this problem, let


(x_1,y_1)=(-3,2)\\m=1

Input these values into the point-slope form equation and convert to slope-intercept form,


y-(2)=(1)[x-(-3)]\\y-2=x+3\\y-2+2=x+3+2\\y=x+5

Next, convert slope-intercept form to standard form:

y=x+5

-x+y=5

For standard form, A must be positive. So,

-(x-y)=5

x-y=-5

User Lewis Buckley
by
8.5k points
7 votes

Answer: y = 1x + 5

Explanation:

This is where the equation; y=mx+b comes in handy.

We are given m, 1.

And we are given a coordinate to plug in.

2=1(-3)+b

2=-3+b

b=5

y = 1x + 5

User Rop
by
8.3k points

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