Question

write an equation in standard form of the line that passes through the given point and has the given slope (-3,2) m=1

Answer 1

Explanation:

The standard form of a line is Ax+By=C. To solve this problem, begin with the point-slope form
`y-y_1=m(x-x_1)`. For this problem, let

`(x_1,y_1)=(-3,2)\\m=1`

Input these values into the point-slope form equation and convert to slope-intercept form,

`y-(2)=(1)[x-(-3)]\\y-2=x+3\\y-2+2=x+3+2\\y=x+5`

Next, convert slope-intercept form to standard form:

y=x+5

-x+y=5

For standard form, A must be positive. So,

-(x-y)=5

x-y=-5

Answer 2

Answer: y = 1x + 5

Explanation:

This is where the equation; y=mx+b comes in handy.

We are given m, 1.

And we are given a coordinate to plug in.

2=1(-3)+b

2=-3+b

b=5

y = 1x + 5