Answer:
She will not be correct
Explanation:
Given data
Length=10in
Width=7in
Height=3in
The volume of the toolbox
V=10*7*3
V=210 in^3
Let us double the volume and see
2V= 210*2
=420 in^3
Let us also double the individual dimensions
Length=20
Width=14in
Height=6in
V= 20*14*6
V=1680 in^3
Hence the volume will be different, she will not be correct