Question

Which is the equation for a line that passes through
the points (-6, -13) and (-12, 5)?

Answer 1

y = -3x - 31

Explanation:

y = mx + b

`m=(y_(2)-y_(1))/(x_(2)-x_(1))`

`m=(5-(-13))/(-12-(-6))`

`m=(18)/(-6)`

m = -3

y = -3x + b

-13 = -3(-6) + b

-13 = 18 + b

b = -13 - 18

b = -31