Question

a spring is stretched from 0.500 m to 0.800 m. assume the unstretched position is 0.00 m. if the spring constant of the spring is 10.0 n/m, what is the work done on the spring?

Answer 1

.45 J

Step-by-step explanation:

The work is also equal to the EPE of the spring and is given by

1/2 k x^2

= 1/2 ( 10 n/m) (.8-.5)^2 = .45 J