Question

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Answer 1

`x = -2`

Explanation:

`\textsf {Square both sides:}\\\\(√(3x+12) )^2 = 3x + 12\\\\(√(x+8) )^2 = x + 8`

(The square of the square root of a value is the value itself

`(√(x) )^2 \;is\;x`)

The original identity then becomes

`3x + 12 = x + 8\\\\3x - x = 8 - 12\\\\2x = -4\\\\x = -4/2\\\\x = -2`