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What is an equation of the line that passes through the points (-2,-6) and (-8,0) ?

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What is an equation of the line that passes through the points (-2,-6) and (-8,0) ? Answer-example-1
User Alves
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Considering the expression of a line, the equation of the line that passes through the pair of points (-2,-6) and (-8,0) is y=-1x -8.

Linear equation

A linear equation o line can be expressed in the form y = mx + b

where

x and y are coordinates of a point.

m is the slope.

b is the ordinate to the origin and represents the coordinate of the point where the line crosses the y axis.

Knowing two points (x₁, y₁) and (x₂, y₂) of a line, the slope m of said line can be calculated using:

m= (y₂ - y₁)÷ (x₂ - x₁)

Substituting the value of the slope m and the value of one of the points in the expression y = mx + b, the value of the ordinate to the origin b can be obtained.

Equation in this case

In this case, being (x₁, y₁)= (-2, -6) and (x₂, y₂)= (-8,0), the slope m can be calculated as:

m= (0 - (-6))÷ (-8 - (-2))

m= (0 +6)÷ (-8 +2)

m= 6÷ (-6)

m= -1

Considering point 2 and the slope m, you obtain:

0= -1×(-8) + b

0= 8 +b

0 -8= b

-8= b

Finally, the equation of the line is y=-1x -8.

User Vishal Vyas
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