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The 3rd term in a geometric sequence is -18 and the 6th term is 9216.

Find the a) common ratio, b) the first term a1, and c) the 4th term a4 in this geometric sequence.

User ProtoVB
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1 Answer

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Answer: The common ratio of the geometric sequence is 1/2, the first term is -72, and the 4th term is -9.

Step-by-step explanation: The common ratio r of a geometric sequence is found by dividing the second term by the first term, and the nth term of the geometric sequence is given by a1 * r^(n-1), where a1 is the first term.

To find the common ratio r of this geometric sequence, we can use the fact that the 3rd term is -18 and the 6th term is 9216:

-18 = a1 * r^2

9216 = a1 * r^5

Dividing these two equations, we get:

-18/9216 = (a1 * r^2) / (a1 * r^5)

-18/9216 = r^-3

r = (-18/9216)^(-1/3)

Since r is the common ratio, it must be positive. Since (-18/9216)^(-1/3) is negative, we must take the positive root:

r = ((-18/9216)^(-1/3))^(1/3)

r = ((-18/9216)^(1/9))

r = (9216/-18)^(1/9)

r = (-512)^(1/9)

r = (-8)^(1/9)

r = (-2)^(2/9)

r = (-2)^(2/3)

r = (1/4)^(2/3)

r = 1/2

To find the first term a1, we can use the fact that the 3rd term is -18 and the common ratio is 1/2:

-18 = a1 * (1/2)^2

-18 = a1/4

a1 = -72

To find the 4th term a4, we can use the fact that the first term is -72 and the common ratio is 1/2:

a4 = (-72) * (1/2)^3

a4 = -9

Therefore, the common ratio of the geometric sequence is 1/2, the first term is -72, and the 4th term is -9.

User Kshepherd
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