Solve for r -2r+15=-3(-2r-7)-6

Question

asked Mar 26, 2023 27.0k views

2 Answers

Chitresh · Answer 1 · 2023-03-28T06:14:04+0000

Answer:

r=0

Explanation:

-2r+15=-3(-2r-7)-6

-2r+15= 6r+21-6

-2r+15=6r+15

-6r. -6r

-8r+15=15

-15. -15

-8r=0

/-8. /-8

r=0

hopes this helps

Stalinko · Answer 2 · 2023-03-31T15:20:19+0000

Answer:

$\bf r=0$

Explanation:

$\bf -2r+15=-3\left(-2r-7\right)-6$

Expand: *-3(-2r-7)-6 = 6r+15* :-

$\bf -2r+15=6r+15$

Subtract 6r from both sides:-

$\bf -2r+15-6r=6r+15-6r$

$\bf -8r+15=15$

Subtract 15 from both sides:-

$\bf -8r+15-15=15-15$

$\bf -8r=0$

Divide both sides by -8:-

$\bf \cfrac{-8r}{-8}=\cfrac{0}{-8}$

$\bf r=0$

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