Question

What is the mass of sodium iodide in 50.0 ml of 2.65 x 10^-2 M Nal (aq)?

0.00877 g
78.8 g
0.0788 g
0.00132 g
0.197 g

Answer 1

To find the mass of sodium iodide in a given volume of a solution, we can use the formula mass and the molar concentration of the solution. In this case, the mass of sodium iodide in 50.0 ml of 2.65 x 10^-2 M Nal (aq) is approximately 0.198 g.

Step-by-step explanation:

To determine the mass of sodium iodide in 50.0 ml of 2.65 x 10^-2 M Nal (aq), we can use the formula mass and the molar concentration of the solution.

First, we need to convert the volume of the solution into liters by dividing 50.0 ml by 1000 (1 L = 1000 ml). The result is 0.050 L.

The number of moles of sodium iodide (NaI) can be calculated by multiplying the volume of the solution in liters (0.050 L) by the molar concentration (2.65 x 10^-2 M).

Moles = volume (L) x concentration (M) = 0.050 L x 2.65 x 10^-2 M = 0.001325 moles.

Finally, to convert moles to grams, we multiply the number of moles (0.001325 moles) by the molar mass of NaI, which is 149.89 g/mol.

Mass of NaI = moles x molar mass = 0.001325 moles x 149.89 g/mol = 0.198 g.

The mass of sodium iodide in 50.0 ml of 2.65 x 10^-2 M Nal (aq) is approximately 0.198 g.

Answer 2

correct answer is 0.197 g!

Step-by-step explanation:

To find the mass of sodium iodide in 50.0 ml of 2.65 x 10^-2 M Nal (aq), you need to first determine the moles of sodium iodide present in the solution. You can do this by using the concentration of the solution and the volume of the solution.

First, convert the concentration of the solution from molarity to moles per liter: 2.65 x 10^-2 M x (1 L/1000 ml) = 2.65 x 10^-5 moles/ml

Next, multiply the moles per milliliter by the volume of the solution in milliliters to find the total number of moles of sodium iodide present: 2.65 x 10^-5 moles/ml x 50.0 ml = 1.325 x 10^-4 moles

Finally, multiply the number of moles of sodium iodide by its molecular weight to find its mass: 1.325 x 10^-4 moles x 149.89 g/mol = 0.197 g. Therefore, the mass of sodium iodide in 50.0 ml of 2.65 x 10^-2 M Nal (aq) is 0.197 g. This means that the correct answer is 0.197 g.