Question

80 grams of water releases 2550 joules of heat. What is the temperature change of the water? Heat capacity of water is 4.2 J/g°C.

Answer 1

7.59°C

Step-by-step explanation:

Using the formula;

Q = m × c × ∆T

Where;

Q = amount of heat (joules)

m = mass of substance (g)

c = specific heat capacity (J/g°C)

∆T = change in temperature (°C)

According to this question;

m = 80g

c = 4.2 J/g°C.

Q = 2550J

∆T = ?

Using Q = m × c × ∆T

∆T = Q/mc

∆T = 2550 ÷ (80 × 4.2)

∆T = 2550 ÷ 336

∆T = 7.589°C

The change in temperature of water = 7.59°C.