Question

A triangle has vertices D (-2,-4), E (4, -2) and F (1, 7). What is the length of EF?

11/3
-3
6.325
7.892
9.487
2/3
-3/4
11.402

Answer 1

9.487.

Explanation:

To find the length of EF, we can use the distance formula. The distance between two points (x1, y1) and (x2, y2) is given by the following formula:

distance = √((x1 - x2)^2 + (y1 - y2)^2)

We can plug in the coordinates of the two points to find the length of EF:

distance = √((4 - 1)^2 + (-2 - 7)^2)

= √(3^2 + (-9)^2)

= √(9 + 81)

= √90

≈ 9.487

Therefore, the length of EF is approximately 9.487.