Question

Can someone please help me with this calculation? It's a bit confusing for me.

You are calculating the average speed, velocity, and acceleration of a toy car.

I'm not sure what the speed of the toy car was or the acceleration. I only have the times of the meters.
first meter: 2.00, second meter: 4.00, third meter: 6.20, fourth meter: 8.01, fifth meter: 10:13, sixth meter: 12:13, seventh meter: 14:13, eighth meter: 16:14, ninth meter 18:18 and tenth meter: 20:00.

Answer the following questions.
Did the car travel at a constant speed? (Hint: you must calculate the speed at every meter)
What was the average speed of the car?
Describe the overall motion of the car.
What are some practical applications for determining the motion of an object?

Answer 1

Answer: See Explanation

Step-by-step explanation:

Did the car travel at a constant speed?

This means "Is the speed at each interval the same?"

There are 10 intervals for which to calculate from.

For each one, the speed is the distance traveled divided by the time.

Each interval is 1 meter long (distance).

1st: 1 meter / 2.00 s = 0.5 m/s

2nd: 1 meter / (4.00 - 2.00) s = 0.5 m/s

3rd: 1 meter / (6.2 - 4.0) s = 0.454 m/s

Right here you can see that the speed is different, NO is the answer.

Average Speed = total distance divided by total time

v = d / t v = (10 m) / (20:00 s) = 0.5 (m/s)

Describe the overall motion: (continue on with step one to see the total motion over the 10 meters)

4th: 0.552

5th: 0.472

6th: 0.5

7th: 0.5

8th: 0.4975

9th: 5.39

10th: 0.55

Overall motion stayed steady from 0-2 meters, slowed for the 3rd meter, sped up for the 4th, slowed down the 5th, stayed steady until slowing down in the 8th meter, then increased speed til the 10th meter.

Races would be practical applications to see where people/cars pace themselves, push themselves, etc.