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Find the equation of the line that passes through each of the following pairs of points in y=Mx+b form.

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Answer:

To find the equation of the line that passes through two points, we can use the slope-intercept form of the equation of a line, which is y=mx+b, where m is the slope of the line and b is the y-intercept. The slope of the line is given by the formula m = (y2-y1)/(x2-x1), where (x1,y1) and (x2,y2) are the coordinates of the two points the line passes through. Once we have the slope, we can plug it into the slope-intercept form to find the equation of the line.

For example, if the line passes through the points (1,2) and (3,4), we would have:

m = (4-2)/(3-1) = 2/2 = 1

The equation of the line would then be y = 1x + b, where b is the y-intercept. We can find the y-intercept by plugging one of the coordinates into the equation and solving for b. For example, if we plug in (1,2), we get 2 = 1(1) + b, so b = 2 - 1 = 1. Therefore, the equation of the line that passes through (1,2) and (3,4) is y = 1x + 1.

In general, given two points (x1,y1) and (x2,y2), the equation of the line that passes through those points is given by:y = (y2-y1)/(x2-x1)x + b, where b = y1 - (y2-y1)/(x2-x1)x1

You can use this formula to find the equation of the line that passes through any two points.

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