Question

Find the perimeter of the triangle XYZ with verticles X (1, 3) , Y(-4, -1) and 2(4, -1). Round your answer to two decimal places

Answer 1

Answer: 19.65

Step-by-step explanation: The perimeter of the triangle would be the sum of the three distances between each point

between (1, 3) and (-4, -1):
`√((1- -4)^2+(3- -1)^2)`

between (1, 3) and (4, -1):
`√((1-4)^2+ (3- -1)^2)`

between (-4, -1) and (4, -1):
`√((-4-4)^2 + (-1-1)^2)`

Summing these distances up, the result is

`√(41) + √(25) + √(68)`

Which is approximately 19.6493354887

Which rounds to 19.65