![\bold{\huge{\pink{\underline{ Solutions }}}}](https://img.qammunity.org/2023/formulas/mathematics/college/35hulgr1a1uwsvl9gj14eatn6m94jurtz7.png)
Answer 1 :-
We have,
- The area of rectangular floor is 32 m²
- Breath is half of its length
Therefore,
Let the length of the rectangular field be x
So,
Breath of the rectangular field will be x/2
We know that,
![\bold{\red{Area \: of \: rectangle = length}}{\bold{\red{*{ Breath}}}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/6j8g2egtrugarbrfyr0s9g3u0knl8vjojx.png)
Subsitute the required values,
![\sf{32 = x }{\sf{*{(x)/(2)}}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/8fqyu4tft7qczr7i96g1sa9aidnceelciz.png)
![\sf{32 = }{\sf{(x^(2))/(2)}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/nh0kxsqj9c064beo75h6x8wfwjvmujq4mc.png)
![\sf{ 32}\sf{*{ 2 = x^(2)}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/hiaecngu1427rqgbk26t477trvzco5cp6b.png)
![\sf{ 64 = x^(2)}](https://img.qammunity.org/2023/formulas/mathematics/high-school/u0gp4lzri5f89uboe3t25t9ewi0vkhnj0u.png)
![\bold{ x = 8 m}](https://img.qammunity.org/2023/formulas/mathematics/high-school/cpam0va9jagstxwhi8uis1ovegxc0vs6ym.png)
Thus, The length of rectanglular field is 8m
Therefore,
Breath of the rectangular field will be
![\sf{=}{\sf{(8)/(2)}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/la8v0lek1yztm43vx297l07g3p45ipra44.png)
![\bold{ = 4 m }](https://img.qammunity.org/2023/formulas/mathematics/high-school/ltma03rvlh7e3zdwr36jntit3b5kve0yid.png)
Now,
We have to find the perimeter of the given rectangular field
We know that,
Perimeter of the reactangle
![\bold{\blue{ = 2( L + W) }}](https://img.qammunity.org/2023/formulas/mathematics/high-school/pek5hy09vhljnstf2j3ttnwi30wl2wbw32.png)
Subsitute the required values in the above formula :-
Perimeter of the rectangular field
![\sf{ = 2( 8 + 4) }](https://img.qammunity.org/2023/formulas/mathematics/high-school/rjw9bhrvcbop8n77n9gx7ziw4etdqdeehh.png)
![\sf{ = 2}{\sf{*{12}}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/qn4tmnk1uv3snbr5t6b5a196hxtdqlains.png)
![\bold{ = 24 m}](https://img.qammunity.org/2023/formulas/mathematics/high-school/kxuf58yuujrvu2blkhwqp8ajx88swj94pp.png)
Hence, The perimeter of the rectangular field is 24 m
Answer 2 :-
We have
- The perimeter of square is 12 cm
Let the side of the square be x
We know that,
![\bold{\pink{ Perimeter\: of\: square = 4 }}{\bold{\pink{*{ side}}}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/kafebed93sdtabxpnpho2bsr676y2p85qw.png)
Subsitute the required values in the above formula :-
![\sf{12 = 4 }{\sf{*{ x }}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/gynkrs9zxsz4cmg14nwqfj6yvgmkmbscu6.png)
![\sf{( 12)/(4)}{\sf{ = x }}](https://img.qammunity.org/2023/formulas/mathematics/high-school/5oev7f8moih81bo5lg8rzc16eebk2cp4ga.png)
![\bold{ x = 3 cm}](https://img.qammunity.org/2023/formulas/mathematics/high-school/4p24wcjwyimswv7gt9mknksniag1rwna18.png)
Thus, The length of the square is 3 cm
Now,
We have to find the area of square
We know that,
![\bold{\red{Area \: of \: square = Side }}{\bold{\red{*{ Side}}}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/5yvgqc3td52paz0e9utl8k02n3dgaqiuz2.png)
Subsitute the required values,
Area of square
![\sf{ = 3 }{\sf{*{ 3 }}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/yrcq3h2hy9viwc7irix5fi2pdld2ducc8i.png)
![\sf{ = 9 cm^(2)}](https://img.qammunity.org/2023/formulas/mathematics/high-school/eoy14l4yhsev2rp203nkon01dun14xlcyl.png)
Hence , The length and area of square is 3cm and 9 cm²
Answer 3 :-
We have
- The perimeter of square feild is 60 m
Let the side of the square feild be x
We know that,
![\bold{\pink{ Perimeter\: of\: square = 4 }}{\bold{\pink{*{ side}}}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/kafebed93sdtabxpnpho2bsr676y2p85qw.png)
Subsitute the required values,
![\sf{60 = 4 }{\sf{*{ x }}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/njjjt1apxc2hl6cehvg45tk9m4hn0pp7nb.png)
![\sf{( 60)/(4)}{\sf{ = x }}](https://img.qammunity.org/2023/formulas/mathematics/high-school/mwrspq4acrxmbla7ln3l160thdsi29xvfg.png)
![\bold{ x = 15 m }](https://img.qammunity.org/2023/formulas/mathematics/high-school/52xnj5i8i8g4ou0094jv35mjcjtvgh97pt.png)
Thus, The side of the square feild is 15m
Now,
We have to find the area of square
We know that,
![\bold{\red{Area \: of \: square = Side }}{\bold{\red{*{ Side}}}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/5yvgqc3td52paz0e9utl8k02n3dgaqiuz2.png)
Subsitute the required values,
Area of square
![\sf{ = 15 }{\sf{*{ 15 }}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/vv1qjvae4t99oe2f9v73julgpi3hlpfkkk.png)
![\sf{ = 225 cm^(2)}](https://img.qammunity.org/2023/formulas/mathematics/high-school/v8wg7pfbzmpyg84lqplw3kx5mgnbf15nor.png)
Hence, The area of square feild is 225 cm²
Answer 4 :-
We have,
- The perimeter of rectangle is 28 cm
- The length of rectangle is 8 cm
Let the breath of the rectangle be x
We know that,
![\bold{\blue{Perimeter\:of\: rectangle= 2( L + W) }}](https://img.qammunity.org/2023/formulas/mathematics/high-school/f4icve74loup5foigmykc40eeh5hzkcmyi.png)
Subsitute the required values,
![\sf{ 28 = 2( 8 + x) }](https://img.qammunity.org/2023/formulas/mathematics/high-school/ffuhhdun9h5jqlqckci08qtlf7rpxc03y8.png)
![\sf{ 28 = 16 + 2x }](https://img.qammunity.org/2023/formulas/mathematics/high-school/de75g5ys15shx32zk29rddot9kkx6zt3cj.png)
![\sf{ 28 - 16 = 2x }](https://img.qammunity.org/2023/formulas/mathematics/high-school/1tuprg1ep5kodpgboqzrgwglfpb8pi9uhu.png)
![\sf{ 12 = 2x }](https://img.qammunity.org/2023/formulas/mathematics/high-school/x8oyfkht3pbtsjjq2xpfm0shef289pik2q.png)
![\sf{( 12)/(2)}{\sf{ = x }}](https://img.qammunity.org/2023/formulas/mathematics/high-school/zhvw89uijuukapbep6832e455103o4zmgs.png)
![\bold{ x = 6 cm}](https://img.qammunity.org/2023/formulas/mathematics/high-school/4mzj99ffow3l5w2frjlywl3tye6j1j2a5z.png)
Thus, The breath of the rectangle is 6 cm
Now,
We have to find the area of rectangle
We know that,
![\bold{\red{Area \: of \: rectangle = length}}{\bold{\red{*{ Breath}}}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/6j8g2egtrugarbrfyr0s9g3u0knl8vjojx.png)
Subsitute the required values,
Area of rectangle
![\sf{= 8 }{\sf{*{6}}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/ynac6tyyobp7gjp92k6z0bcwj7ateweate.png)
![\sf{ = 48 cm^(2)}](https://img.qammunity.org/2023/formulas/mathematics/high-school/aocu6o82wku8jx0eoymd0ftilun2hq773g.png)
Hence, The breath and area of rectangle is 6cm and 48 cm² .
[ Note :- Kindly refer app for better understanding ]