Question

Calculate the area of a parallelogram with a base of 10cm and a height of 7cm​

Answer 1

Answer: 70 cm^2

Step-by-step explanation: The formula for a parallelogram is A(area)= b(base) * h(height)

therefore, it would be A = 10 * 7

A = 70 cm^2

Answer 2

Given :-

`\\`

• Base of parallelogram = 10 cm

• Height of Parallelogram = 7 cm

`\\`

To find:

`\\`

• Area of parallelogram

`\\`

we know:-

`\\ \\`

`\bigstar \boxed{ \rm Area \: of \: parallelogram = base * height}`

`\\ \\`

So:-

`\dashrightarrow\sf Area \: of \: parallelogram = base * height \\`

`\\ \\`

`\dashrightarrow\sf Area \: of \: parallelogram =10 * 7 \\`

`\\ \\`

`\dashrightarrow\sf Area \: of \: parallelogram =70 {cm}^(2) \\`

`\\ \\`

`\therefore \underline{\bf Area \: of \: parallelogram is \: equal \: to \red{ 70 {cm}^(2)}}`

`\\ \\`

Know More:-

`\small\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf \small{Formulas\:of\:Areas:-}}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length* Breadth \\\\ \star\sf Triangle=(1)/(2)* Base* Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\frac {1}{2}* d_1* d_2 \\\\ \star\sf Rhombus =\:\frac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Base* Height\\\\ \star\sf Trapezium =\frac {1}{2}(a+b)* Height \\ \\ \star\sf Equilateral\:Triangle=\frac {√(3)}{4}(side)^2\end {array}}\end{gathered}\end{gathered}\end{gathered}`