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The body temperatures of adults are normally distributed with a mean of 98.6° F and a standard deviation of 0.86° F. What temperature represents the 95th percentile?

The body temperatures of adults are normally distributed with a mean of 98.6° F and a standard deviation of 0.86° F. What temperature represents the 95th percentile?
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The body temperatures of adults are normally distributed with a mean of 98.6° F and a standard deviation of 0.86° F. What temperature represents the 95th percentile?

User Mohammad Asghari
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1 Answer

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Z = (x - mean)/ (standard deviation)
1-0.95 = 0.05,
0.05 * 0.86 + 98.6 = x, x = 98.643.
User Ivri
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