Question

Y-2/3x=-6. Find the value of x.

Answer 1

`y-(2)/(3) x=-6`

Add -y to both sides:

`(-2)/(3) x+y+-y=-6+-y`

`(-2)/(3) =-y-6`

Divide both sides by
`(-2)/(3)`:

`((-2)/(3)x )/((-2)/(3) ) =(-y-6)/((-2)/(3) )`

`\fbox{x = $(3y+18)/(2) $}`