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What is the maximum mass of pure silver that could be extracted from 80.0 g of argentite, a silver ore with the chemical formula Ag₂S?

Be sure your answer has a unit symbol, if necessary, and is rounded to 3 significant digits.

1 Answer

2 votes

Answer:

69.647g Ag

Step-by-step explanation:

First, determine the molecular weight of
Ag_2S:

Atomic Mass Ag = 107.87
(g)/(mol)

Atomic Mass S = 32.07
(g)/(mol)

So,

Molecular Weight
Ag_2S = 2(107.87
(g)/(mol))+(32.07
(g)/(mol))

Molecular Weight
Ag_2S=247.81
(g)/(mol)

Then determine the mass of silver contained in the sample:


80.0gAg_2S((1molAg_2S)/(247.81g))((2molAg)/(1molAg_2S))((107.87gAg)/(1molAg))=69.647gAg

This answer makes sense because the mass of silver in the compound must be less than the total mass of the compound.

User Duvo
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