Question

If y varies jointly as x and z and y = 4 when x = 2 and z = 3, what is y when x = -6 and z = 2?

Answer 1

Explanation:

Y = kxz

Putting values of y x and z in the equation

4 = k(2)(3)

4 = k6

2/3 = k

Now finding y when x = - 6 and z = 2

Y = kxz

= 2/3(-6)(2)

= - 8