Answer:
(a) 30 -10t = 0
Explanation:
Given a relation between time (t) and temperature (T), you want to know the condition that will describe when T reaches an extreme.
10·ln(15t³) -2T +100 = T +10t
Extreme
The temperature T will be at an extreme when the derivative with respect to t is 0.
Simplifying the logarithm, we can write ...
10·(ln(15) +3·ln(t)) -2T +100 = T +10t
Differentiating with respect to t gives ...
10(0 +3/t) -2T' +0 = T' +10
Setting T' to zero, we have the equation ...
30/t = 10
30 = 10t . . . . . multiply by t
30 -10t = 0 . . . . matches choice A
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