Question

One number is three less than twice another . the sum of their square is 117 . find the numbers.​

Answer 1

-10.2 and -7.2

6 and 9

Explanation:

Let the numbers be x and y.

x² + y² = 117

y = 2x - 3

x² + (2x - 3)² = 117

x² + 4x² - 12x + 9 = 117

5x² - 12x - 108 = 0

(5x + 18)(x - 6) = 0

5x + 18 = 0 or x - 6 = 0

x = -18/5 or x = 6

x = -3.6 or x = 6

y = 2x - 3

y = 2(-3.6) - 3

y = -10.2

y = 2x - 3

y = 2(6) - 3

y = 9

Answer:

-3.6 and -10.2

6 and 9